A) 16.65 mL
B) 22.20 mL
C) 5.55 mL
D) 11.10 mL
Correct Answer: C
Solution :
Molarity of \[{{H}_{2}}S{{O}_{4}}\] solution \[=\,\,\frac{98\times 1000}{98\times 100}\,\times \,1.802\,\,=\,\,18.02\] Suppose V ml of this \[{{H}_{2}}S{{O}_{4}}\] is used to prepare 1 litre of 0.1 M \[{{H}_{2}}S{{O}_{4}}\]. Using formula \[{{M}_{1}}{{V}_{1}}\,=\,\,{{M}_{2}}{{V}_{2}}\] \[\therefore \,\,~V\times 18.02 =1000\times 0.1\] \[V=\frac{1000\times 0.1}{18.02}\,\,=\,\,5.55\,\,ml\]
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