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NEET Sample Paper NEET Sample Test Paper-67

  • question_answer
    If there are no heat losses, the heat released by the condensation of x gram of steam at \[100{}^\circ \,C\] into water at \[100{}^\circ \,C\] can be used to convert y gram of ice at \[0{}^\circ C\] into water at\[100{}^\circ \,C\]. Then the ratio \[\operatorname{y}\,\,:\, x\] is nearly

    A) \[1:1\]               

    B) \[2.5 : 1\]

    C) \[2 : 1\]             

    D) \[3 : 1\]

    Correct Answer: D

    Solution :

    Heat released to convert x gm of steam at \[100{}^\circ C\]to water at \[100{}^\circ C\] is \[x\,\,\times \,\,540\] cals. If y gm of ice is converted from \[\,0{}^\circ C\] to water at \[100{}^\circ C\] it requires heat \[y\times 80+y\times 1\times 100=180\,\text{y}\] \[\therefore \,\,\,x\times 540=180\,y\,\,\,\,or\,\,\,\,\frac{y}{x}=\frac{540}{180}=\frac{3}{1}\]


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