A) \[Period = {{3}^{rd}}, block = p, group =16\]
B) \[Period = {{5}^{th}}, block = s, group = 1\]
C) \[Period = {{3}^{rd}}, block = p, group = 10\]
D) \[Period={{4}^{th}}, block = d, group = 12\]
Correct Answer: A
Solution :
By observing principal quantum number (n), orbital (s, p, d, f) and equating no. of \[{{e}^{-}}\]s we are able to find the period, block and group of element in periodic table.You need to login to perform this action.
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