A) T
B) 3T
C) 9T
D) \[3\sqrt{3}\,T\]
Correct Answer: A
Solution :
Time period of satellite which is very near to planet \[T=2\pi \sqrt{\frac{{{R}^{3}}}{GM}}=2\pi \sqrt{\frac{{{R}^{3}}}{G\frac{4}{3}\pi {{R}^{3}}\rho }}\,\,\,\,\,\,\,\,\,\,\,\therefore \,\,T\propto \sqrt{\frac{1}{\rho }}\] i.e. time period of nearest satellite does not depend upon the radius of planet, it only depends upon the density of the planet. In the problem, density is same so time period will be same.You need to login to perform this action.
You will be redirected in
3 sec