A) \[\frac{{{E}_{1}}{{E}_{2}}({{\lambda }_{1}}-{{\lambda }_{2}})}{{{\lambda }_{1}}{{\lambda }_{2}}}\]
B) \[\frac{{{E}_{1}}{{\lambda }_{1}}-{{E}_{2}}{{\lambda }_{2}})}{({{\lambda }_{1}}-{{\lambda }_{2}})}\]
C) \[\frac{{{E}_{1}}{{\lambda }_{1}}-{{E}_{2}}{{\lambda }_{2}})}{({{\lambda }_{2}}-{{\lambda }_{1}})}\]
D) \[\frac{{{\lambda }_{1}}{{\lambda }_{2}}-{{E}_{1}}{{E}_{2}}}{({{\lambda }_{2}}-{{\lambda }_{1}})}\]
Correct Answer: C
Solution :
\[E={{W}_{0}}+{{K}_{\max }}\] \[\Rightarrow \,\,\,\,\,\frac{hc}{{{\lambda }_{1}}}={{W}_{0}}+{{E}_{1}}\,\,and\,\,\frac{hc}{{{\lambda }_{2}}}\,={{W}_{0}}+{{E}_{2}}\] \[\Rightarrow \,\,hc={{W}_{0}}{{\lambda }_{1}}+{{E}_{1}}{{\lambda }_{1}}\,and\,\,hc={{W}_{0}}{{\lambda }_{2}}+{{E}_{2}}{{\lambda }_{2}}\] \[\Rightarrow \,\,\,{{W}_{0}}{{\lambda }_{1}}+{{E}_{1}}{{\lambda }_{1}}\,=\,\,{{W}_{0}}{{\lambda }_{2}}+{{E}_{2}}{{\lambda }_{2}}\] \[\Rightarrow \,\,\,{{W}_{0}}=\frac{{{E}_{1}}{{\lambda }_{1}}-{{E}_{2}}{{\lambda }_{2}}}{({{\lambda }_{2}}-{{\lambda }_{1}})}\]You need to login to perform this action.
You will be redirected in
3 sec