A) \[\frac{4}{3}\,\left( \frac{{{\lambda }_{2}}}{{{\lambda }_{1}}} \right)\]
B) \[\frac{4}{3}\,\left( \frac{{{\lambda }_{1}}}{{{\lambda }_{2}}} \right)\]
C) \[\frac{3}{4}\,\left( \frac{{{\lambda }_{2}}}{{{\lambda }_{1}}} \right)\]
D) \[\frac{3}{4}\,\left( \frac{{{\lambda }_{1}}}{{{\lambda }_{2}}} \right)\]
Correct Answer: B
Solution :
Position of m maxima from central maxima is given by \[{{x}_{n}}=\,\,\frac{n\lambda D}{d}\] \[\Rightarrow \,\,\,{{x}_{n}}\propto n\lambda \,\,\,\,\Rightarrow \,\,\,\frac{{{d}_{1}}}{{{d}_{2}}}\,=\,\frac{{{n}_{1}}{{\lambda }_{1}}}{{{n}_{2}}{{\lambda }_{2}}}\,=\,\,\frac{8{{\lambda }_{1}}}{6{{\lambda }_{2}}}\,=\,\frac{4}{3}\,\left( \frac{{{\lambda }_{1}}}{{{\lambda }_{2}}} \right)\]You need to login to perform this action.
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