A) \[\frac{M\,\,\sin \,\,\theta }{1-\,\sin \,\,\theta }\]
B) \[\frac{M\,\,\cos \,\,\theta }{1+\,\,\sin \,\,\theta }\]
C) \[\frac{M\,\,\sin \,\,\theta }{1+\,\,\sin \,\,\theta }\]
D) \[\frac{M\,\,\cos \,\,\theta }{1-\,\,\sin \,\,\theta }\]
Correct Answer: A
Solution :
\[T=mg\] \[f=Mg\,\sin \text{ }\theta \,\,+\,\,T\,\sin \,\theta \] \[\Rightarrow \,\,f=Mg\,\sin \text{ }\theta \,\,+\,\,mg\,\sin \,\theta \] Balancing torque about \[\operatorname{C}:Tr =fr\] \[\Rightarrow \,\,\,\operatorname{mg} = Mg\,\,sin\theta + mg\,sin\,\theta \] \[m=\,\,\frac{M\,\,\sin \,\theta }{1-\sin \,\theta }\]You need to login to perform this action.
You will be redirected in
3 sec