A) \[3\,\,\times \,\,{{10}^{-15}}\,m\]
B) \[1.5\,\,\times \,\,{{10}^{-15}}\,m\]
C) \[6\,\,\times \,\,{{10}^{-15}}\,m\]
D) \[4.5\,\,\times \,\,{{10}^{-15}}\,m\]
Correct Answer: C
Solution :
Radius R of a nucleus changes with the nucleon number A of the nucleus as \[R=1.3\times {{10}^{-15}}\,\times {{A}^{1/3}}\,metre\] \[Hence\,\,\frac{{{R}_{2}}}{{{R}_{1}}}{{\left( \frac{{{A}_{2}}}{{{A}_{1}}} \right)}^{1/3}}\,=\,\,{{\left( \frac{128}{16} \right)}^{1/3}}\,=\,\,{{(8)}^{1/3}}\,=\,\,2\]You need to login to perform this action.
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