A) \[{{\left( 2\,\,tan\,\,\theta \right)}^{1/3}}\]
B) \[{{\left( 2\,\,tan\,\,\theta \right)}^{-1/3}}\]
C) \[{{\left( 2\,\,\cot \,\,\theta \right)}^{1/3}}\]
D) \[{{\left( 2\,\,\cot \,\,\theta \right)}^{-1/3}}\]
Correct Answer: C
Solution :
In equilibrium \[{{B}_{1}}={{B}_{2}}\,\tan \,\theta \] \[\Rightarrow \,\,\frac{{{\mu }_{0}}}{4\pi }\cdot \,\frac{2M}{d_{1}^{3}}=\,\,\frac{{{\mu }_{0}}}{4\pi }\cdot \frac{M}{d_{2}^{3}}\,\tan \,\theta \] \[\Rightarrow \,\,\,\frac{{{d}_{1}}}{{{d}_{2}}}\,=\,\,{{(2\,cot\,\theta )}^{1/3}}\]You need to login to perform this action.
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