A) \[\left[ M{{L}^{2}}{{T}^{-}}^{2} \right]\]
B) \[\left[ M{{L}^{-1}}{{T}^{-}}^{2} \right]\]
C) \[\left[ M{{L}^{2}}{{T}^{-}}^{1} \right]\]
D) \[\left[ ML{{T}^{-}}^{1} \right]\]
Correct Answer: B
Solution :
Dimensions of \[{{\varepsilon }_{0}}=\left[ {{M}^{-1}}{{L}^{-3}}{{T}^{4}}{{A}^{2}} \right]\] Dimensions of \[E\,\,=\left[ ML{{T}^{-3}}{{A}^{-1}} \right]\] \[\therefore \] Dimensions of \[\frac{1}{2}{{\varepsilon }_{0}}{{E}^{2}}=\left[ {{M}^{-1}}{{L}^{-3}}{{T}^{4}}{{A}^{2}} \right]\] \[\times \left[ {{M}^{2}}{{L}^{2}}{{T}^{-6}}{{A}^{-2}} \right]=\left[ M{{L}^{-1}}{{T}^{-2}} \right]\]You need to login to perform this action.
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