A) 6 m
B) 4 m
C) \[\frac{10}{3}\,m\]
D) \[\frac{19}{3}\,m\]
Correct Answer: C
Solution :
Distance travelled by the particle in nth second, \[{{S}_{nth}}=u+\frac{1}{2}\,a(2n-1)\] Where u is initial speed and a is acceleration of the particle. \[n=3,\,\,u=0,\,\,a=\frac{4}{3}\,m/{{s}^{2}}\] \[\therefore \,\,\,{{S}_{3rd}}=0+\frac{1}{2}\times \frac{4}{3}\times (2\times 3-1)=\frac{10}{3}\,m\]You need to login to perform this action.
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