A) neutron
B) deutron
C) \[\alpha -particle\]
D) positron
Correct Answer: A
Solution :
\[_{11}N{{a}^{23}}+\,{{\,}_{1}}{{H}^{1}}\,\,\to \,{{\,}_{12}}M{{g}^{23}}+\,{{\,}_{0}}{{n}^{1}}\]You need to login to perform this action.
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