A) oxidation by 3 electrons
B) reduction by 3 electrons
C) oxidation by 5 electrons
D) reduction by 5 electrons
Correct Answer: D
Solution :
\[MnO_{4}^{-}\,\,\to \,\,M{{n}^{2+}}\]. In this reaction \[5{{e}^{-}}\] are needed for the reduction of \[M{{n}^{2+}}\] as: \[MnO_{4}^{-}\,\,+\,\,5{{e}^{-}}\,\to \,\,M{{n}^{2+}}\]You need to login to perform this action.
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