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NEET Sample Paper NEET Sample Test Paper-67

  • question_answer
    Total surface area of a cathode is \[0.05\text{ }{{m}^{2}}\] and 1 A current passes through it for 1 hour. Thickness of nickle deposited on the cathode is (given that density of \[\operatorname{nickle} = 9 g/cc\] and its\[E.C.E.=-\,3.04\times {{10}^{-4}}\,g/C\])

    A) 2.4 m               

    B) \[2.4\,\,\mu m\]

    C) \[2.4\,\,\mu m\]             

    D) None of these

    Correct Answer: C

    Solution :

    \[\operatorname{Mass} deposited = Density \times  Volume of the metal\] \[m=p\times A\times X\]                                      ... (i) Hence from Faraday?s first law \[\operatorname{m} = Zit\] ?.(ii) So from equations (i) and (ii) \[Zit\,\,=\,\,\rho \times Ax\Rightarrow \,\,x=\frac{Zit}{\rho A}\] \[=\,\,\frac{3.04\times {{10}^{-4}}\times {{10}^{-3}}\times 1\times 3600}{9000\times 0.05}\] \[=2.4\times 1{{0}^{-\,6}}m\,\,=\,\,2.4\,\,\mu m\]


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