A) \[7\text{ }m/{{s}^{2}}\]
B) \[\sqrt{7}\text{ }m/{{s}^{2}}\]
C) \[5\text{ }m/{{s}^{2}}\]
D) \[1\text{ }m/{{s}^{2}}\]
Correct Answer: C
Solution :
\[Average\,\,acceleration\,\,=\,\,\frac{Change\,\,in\,\,velocity}{Total\,\,time}\] \[\overrightarrow{{{\nu }_{L}}}=\,\,30\hat{i}\,\,m/s\,\,and\,\,{{\vec{v}}_{i}}=40\hat{j}m/s\] \[\left| \Delta \vec{\nu } \right|=\sqrt{{{30}^{2}}+{{40}^{2}}}=\,\sqrt{900+1600}\,\,=\,\,50\,m/s\] \[\vec{a}=\frac{\left| {{{\vec{V}}}_{f}}-{{{\vec{V}}}_{i}} \right|}{\Delta t}\,\,=\,\,\frac{50}{10}\,\,=\,\,5\,m{{s}^{-2}}\]You need to login to perform this action.
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