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NEET Sample Paper NEET Sample Test Paper-67

  • question_answer
    A capacitor of capacitance \[{{C}_{1}}=1\,\,\mu F\] can withstand maximum voltage \[{{V}_{1}}\,\,=\,\,6\,\,kV\] (kilo volt) and another capacitor of capacitance \[{{C}_{2}}=3\,\,\mu F\] can withstand maximum voltage\[{{V}_{2}}\,\,=\,\,4\,\,kV\]. When the two capacitors are connected in series, the combined system can withstand a maximum voltage of                 

    A) 4 kV                 

    B) 6 kV         

    C) 8 kV                 

    D) 10 kV        

    Correct Answer: C

    Solution :

    We know \[Q=CV\] Hence \[{{({{Q}_{1}})}_{max}}=6\,mC\,\,while\,\,{{({{Q}_{2}})}_{max}}\,=\,12\,mC\] However in series charge is same so maximum charge on \[{{C}_{2}}\] will also be 6 mC (and not 12 mC) and hence potential difference across \[{{C}_{2}}\] will be \[{{V}_{2}}\,=\frac{6mC}{3\mu F}=\,\,2\,kV\] and as in series \[V={{V}_{1}}+{{V}_{2}}\] So \[{{V}_{\max }}\,\,=\,\,6\,kV\,\,+\,\,2kV\,\,=\,\,8kV\]


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