A) 90.2 m
B) 89.6 m
C) 86.6 m
D) 70.2 m
Correct Answer: C
Solution :
\[Total\,\,time\,of\,flight=\frac{2\,u\,\sin \,\theta }{g}=\frac{2\times 50\times 1}{2\times 10}\,\,=\,\,5\,s\] \[\operatorname{Time} to cross the wall = 3 sec \left( given \right)\] \[\operatorname{Time} in air after crossing the wall = \left( 5 - 3 \right)\] \[= 2 sec\] \[\therefore \] Distance travelled beyond the wall =\[(u\,cos\,\theta )t\] \[=\,\,50\times \frac{\sqrt{3}}{2}\,\times 2=86.6\,m\]
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