NEET Sample Paper NEET Sample Test Paper-67

  • question_answer
    In an experiment four quantities a, b, c and d are measured with percentage error \[1%,\text{ }2%,\text{ }3%\text{ }and\text{ }4%\] respectively. Quantity P is calculated as follows: \[P=\frac{{{a}^{3}}{{b}^{2}}}{cd}%\]

    A) \[14\,%\]                       

    B) \[10\,%\]

    C) \[7\,%\]                         

    D) \[4\,%\]

    Correct Answer: A

    Solution :

    \[P=\frac{{{a}^{3}}{{b}^{2}}}{cd}\] \[\Rightarrow \,\,\,\frac{\Delta P}{P}\times 100=3\left( \frac{\Delta a}{a}\times 100 \right)+2\left( \frac{\Delta b}{b}\times 100 \right)\] \[\left( \frac{\Delta c}{c}\times 100 \right)+\left( \frac{\Delta d}{d}\times 100 \right)\] \[=3\times 1+2\times 2+3+4\] \[=3+4+3+4=14%\]


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