A) Cu
B) Ag
C) Fe
D) Na
Correct Answer: B
Solution :
\[A{{g}_{2}}S+4NaCN\,\,\rightleftharpoons \,\,2Na\underset{Sodium\,\,dicyno\,\,\arg entate}{\mathop{\left[ Ag{{(CN)}_{2}} \right]}}\,+N{{a}_{2}}S\] \[2Na\left[ Ag{{(CN)}_{2}} \right]\,\,+\,\,Zn\,\,\to \,\,\underset{Sodium\,\,tetracyno\,\,zincate\,\,(ppt)}{\mathop{N{{a}_{2}}\left[ Zn{{(CN)}_{4}} \right]\,\,+\,\,2Ag\downarrow }}\,\]
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