A) \[1.28 \times 1{{0}^{-}}^{2}\]
B) \[6.4 \times 1{{0}^{-}}^{3}\]
C) \[9.6 \times 1{{0}^{-}}^{3}\]
D) \[3.2 \times 1{{0}^{-}}^{4}\]
Correct Answer: B
Solution :
As we know that the velocity constant becomes double by increasing the temperature by \[10{}^\circ C\] so if at 290 K, velocity constant \[= 3.2 \,\times \, 1{{0}^{-3}}\] then at 300 K, velocity constant\[=2({{K}_{290}})\,\,=\,\,2\times 3.2\times {{10}^{-3}}=6.4\times {{10}^{-3}}\].
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