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NEET Sample Paper NEET Sample Test Paper-67

  • question_answer
    Time period of revolution of a nearest satellite around a planet of radius R is T. Period of revolution around another planet, whose radius is 3R but having same density is

    A) T                                 

    B) 3T

    C) 9T                               

    D) \[3\sqrt{3}\,T\]

    Correct Answer: A

    Solution :

    Time period of satellite which is very near to planet \[T=2\pi \sqrt{\frac{{{R}^{3}}}{GM}}=2\pi \sqrt{\frac{{{R}^{3}}}{G\frac{4}{3}\pi {{R}^{3}}\rho }}\,\,\,\,\,\,\,\,\,\,\,\therefore \,\,T\propto \sqrt{\frac{1}{\rho }}\] i.e. time period of nearest satellite does not depend upon the radius of planet, it only depends upon the density of the planet. In the problem, density is same so time period will be same.


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