A) \[1/2\text{ }atm\]
B) \[1/273\text{ }atm\]
C) 2 atm
D) 273 atm
Correct Answer: A
Solution :
\[{{T}_{1}}=273{}^\circ C=273+273{}^\circ C=546\,K\] \[{{T}_{2}}=0{}^\circ C=273+0{}^\circ C=273\,\,K\] \[{{P}_{1}}=1;\,\,{{P}_{2}}\,=\,\,?\] According to Gay-Lussac?s law \[\frac{{{P}_{1}}}{{{T}_{1}}}=\frac{{{P}_{2}}}{{{T}_{2}}}\,\,\,\,\,\,\,\therefore \,\,\,\,{{P}_{2}}=\frac{{{P}_{1}}{{T}_{2}}}{{{T}_{1}}}\,\,=\,\,\frac{1\times 273\,K}{546\,K}\,atm;\] \[=\,\,\,\frac{1}{2}\,\,atm\]
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