A) curves have the same slope and do not intersect
B) curves must intersect at some point other than \[T=0\]
C) curve for \[{{V}_{2}}\] has a greater slope than that for \[{{V}_{1}}\]
D) curve for \[{{V}_{1}}\] has a greater slope than that for \[{{V}_{2}}\]
Correct Answer: C
Solution :
At constant volumes \[P\propto T\] \[\operatorname{P}= constant T;\,\,PV = nRT \,\,\,\therefore \,\, P\,\,=\,\,\frac{nR}{V}T\] \[Slope\,\,=\,\,m=\frac{nR}{V}\,\,\,\,\because \,\,{{V}_{2}}<{{V}_{1}}\] \[\frac{{{m}_{1}}}{{{m}_{2}}}=\frac{{{V}_{2}}}{{{V}_{1}}}\,\,\,\,\,\,\,\,\therefore \,\,\,{{m}_{1}}<{{m}_{2}}\] is curve for \[{{V}_{2}}\] has a greater slope than for \[{{V}_{1}}\]You need to login to perform this action.
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