A) alkaline
B) acidic
C) strongly acidic
D) neutral
Correct Answer: D
Solution :
For NaOH, \[M=\text{N}\] \[{{N}_{1}}{{V}_{1}}=100\,ml\,\times \,1\,N\,\,=\,\,100\,ml\,(N)\] For \[{{\operatorname{H}}_{2}}S{{O}_{4}},\,\,{{N}_{2}}{{V}_{2}}\,\,=\,\,10ml\,\,\times \,\,10\,N\,\,=\,\,100\,\,ml\,(N)\] Hence, \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\].You need to login to perform this action.
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