A) Add 0.585 g NaCl
B) Add 20 ml water
C) Add 0.001 ml NaCl
D) Evaporate 10 ml water
Correct Answer: A
Solution :
100 ml of \[0.30\,M\,\,=\,\,\frac{100\times 0.3}{1000}\,=\,0.03\] mole of NaCl 100 ml of \[0.40\,M\,\,=\,\,\frac{100\times 0.4}{1000}\,\,=\,\,0.04\] mole of NaCl Moles of NaCl to be added \[= 0.04 - 0.03 = 0.01\] \[mole = 0.585 g\]You need to login to perform this action.
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