A) 90
B) 89
C) 67
D) 81
Correct Answer: D
Solution :
Intensity of each source \[=\,\,\,{{I}_{0}}=\frac{100}{4}=25\,unit\] If the intensity of one of the source is reduced by \[36\,% \,then\, {{I}_{1}} = 25 unit\] and \[{{I}_{2}}=25-25\times \frac{36}{100}=16\,(unit)\] Hence resultant intensity at the same point will be \[I={{I}_{1}}+{{I}_{2}}+2\sqrt{{{I}_{1}}{{I}_{2}}}\] \[=25+16+2\sqrt{25\times 16}\,\,=\,\,81\,\,unit\]You need to login to perform this action.
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