A)
B)
C)
D) (d)
Correct Answer: D
Solution :
\[F=-\frac{dU}{dx}\,\,\,\Rightarrow \,\,dU=-Fdx\] \[\Rightarrow \,\,\,U=-\int_{0}^{x}{(-kx+a{{x}^{3}})dx}\] \[\therefore \] We get \[U=0\,\,at\,\,x=0\,\,and\,\,x=\sqrt{\frac{2k}{a}}\] Also we get \[U=negative\,\,for\,\,x>\sqrt{\frac{2k}{a}}\] From the given function we can see that \[\operatorname{F} =0\] at \[\operatorname{x}= 0\], i.e., slope of \[U-x\] graph is zero at \[\operatorname{x} =0\].You need to login to perform this action.
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