A) 10
B) \[5\sqrt{2}\,\]
C) \[10\sqrt{2}\,\]
D) 20
Correct Answer: C
Solution :
Body moves along the parabolic path. For vertical motion : By using \[\operatorname{v} =u + at\] \[\Rightarrow \,\,\,{{\nu }_{y}}=0+\frac{QE}{m}\,\,\cdot \,\,t=\,\,\frac{{{10}^{-6}}\times {{10}^{3}}}{{{10}^{-3}}}\,\,\times 10=10\,m/s\] For horizontal motion-Its horizontal velocity remains the same, i.e., after 10 s, horizontal velocity of body \[{{v}_{x}}\,\,=\,\,10\,m/s.\] Velocity after 10 s \[\nu =\sqrt{\nu _{x}^{2}+\nu _{y}^{2}}\,\,=\,\,10\sqrt{2}\,m/s\]You need to login to perform this action.
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