A) \[12\,\,m{{s}^{-2}}\]
B) \[24\,\,m{{s}^{-2}}\]
C) zero
D) \[6\,\,m{{s}^{-2}}\]
Correct Answer: A
Solution :
\[v=\frac{dx}{dt}=\,\,12-3{{t}^{2}}=0\] ?. (i) If velocity is zero, \[12-3{{t}^{2}}=0\] which gives \[t=0\] sec For acceleration again differential equation (i) At time \[\operatorname{t}=2 sec,\,\,a=-6 \times 2= -12 m/{{s}^{2}}\] Hence retardation \[=\,\,12\,m/{{s}^{2}}\]You need to login to perform this action.
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