A) 93; 211
B) 211; 93
C) 212; 88
D) 88; 211
Correct Answer: A
Solution :
\[_{96}{{X}^{227}}\,\,\to \,\,Y+4\alpha +5\beta \] On equating mass number \[227=y+4\times 4+0,\,\,y=\,\,211\] On equating atomic number \[96=y+2\times 4-5,\,\,y\,\,=\,\,93\]You need to login to perform this action.
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