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NEET Sample Paper NEET Sample Test Paper-69

  • question_answer
    Simple pendulum is executing simple harmonic motion with time period T. If the length of the pendulum is increased by \[21\,%\] then the increase in the time period of the pendulum of the increased length is

    A) \[22%\]             

    B) \[13%\]

    C) \[50%\]             

    D) \[10%\]

    Correct Answer: D

    Solution :

    Time period of simple pendulum \[T=2\pi \sqrt{\frac{l}{g}}\] \[\Rightarrow \,\,\,T\propto \,\,\sqrt{l}\] \[\therefore \,\,\,\,\,\,\,\frac{\Delta l}{T}=\frac{1}{2}\,\frac{\Delta l}{l}\] \[Since,\,\,\,\frac{\Delta l}{l}\,\,=\,\,21\,%\] \[\therefore \,\,\,\,\,\,\,\,\frac{\Delta T}{T}\,\,=\,\,\frac{1}{2}\,\,\times \,\,21\,%\] \[=\,\,10\,%\]


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