A) 0.42 mA
B) 0.49 Ma
C) 0.29 mA
D) 0.35 mA
Correct Answer: C
Solution :
Current gain in common-base amplifier is the ratio of change in collector current to change in emitter current. Current gain of transistor is \[\alpha =\frac{\Delta {{i}_{C}}}{\Delta {{i}_{E}}}\] where \[\Delta {{i}_{C}}\] is change in collector current, and \[\Delta {{i}_{E}}\] is change in emitter current. Given, \[\alpha =0.96,\,\,\Delta {{i}_{E}}=7.2,\] \[\Delta {{i}_{C}}=0.96\times 7.2\text{ }=6.91\,mA\] Also \[\Delta {{i}_{E}}=\Delta {{i}_{C}}+\Delta {{i}_{B}}\] \[\therefore \,\,\,\,\,\,\Delta {{i}_{B}}=\Delta {{i}_{E}}+\Delta {{i}_{C}}\] \[= 7.2 - 6.91 = 0.29 mA\]
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