A) \[22%\]
B) \[13%\]
C) \[50%\]
D) \[10%\]
Correct Answer: D
Solution :
Time period of simple pendulum \[T=2\pi \sqrt{\frac{l}{g}}\] \[\Rightarrow \,\,\,T\propto \,\,\sqrt{l}\] \[\therefore \,\,\,\,\,\,\,\frac{\Delta l}{T}=\frac{1}{2}\,\frac{\Delta l}{l}\] \[Since,\,\,\,\frac{\Delta l}{l}\,\,=\,\,21\,%\] \[\therefore \,\,\,\,\,\,\,\,\frac{\Delta T}{T}\,\,=\,\,\frac{1}{2}\,\,\times \,\,21\,%\] \[=\,\,10\,%\]You need to login to perform this action.
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