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NEET Sample Paper NEET Sample Test Paper-69

  • question_answer
    Velocity of sound waves in air is 330 m/sec. For a particular sound in air, a path difference of 40 cm is equivalent to a phase difference of\[1.6\,\pi \]. The frequency of this wave is

    A) 165 Hz             

    B) 150 Hz

    C) 660 Hz             

    D) 330 Hz

    Correct Answer: C

    Solution :

    \[\operatorname{Phase} difference = \frac{2\pi }{\lambda } \times  path difference\] \[\Rightarrow \,\,\,\,1.6\,\,\pi \,\,=\,\,\frac{2\pi }{\lambda }\times 40 \,\Rightarrow \,\, \lambda =50\,\,cm\,\,=\,\,0.5\,\,m\,\] \[\Rightarrow \,\,\,\,u=n\lambda \,\,\,\,\,\,\Rightarrow \,\,\,\,\,300=0.5\times n\,\,\] \[\Rightarrow \,\,\,n=660\text{ }Hz\]


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