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NEET Sample Paper NEET Sample Test Paper-69

  • question_answer
    A 0.001 molal solution of \[\left[ Pt{{(N{{H}_{3}})}_{4}}C{{l}_{3}} \right]C{{l}_{4}}\] in water had a freezing point depression of\[0.0054{}^\circ C\]. If \[{{K}_{f}}\] for water is 1.80, the correct formulation for the above molecule is

    A) \[\left[ Pt{{\left( NH{_{3}} \right)}_{4}}C{{l}_{3}} \right]Cl\]

    B) \[\left[ Pt{{\left( NH{_{3}} \right)}_{4}}Cl \right]C{{l}_{2}}\]

    C) \[\left[ Pt{{\left( NH{_{3}} \right)}_{4}}C{{l}_{2}} \right]Cl\]

    D) \[\left[ Pt{{\left( NH{_{3}} \right)}_{4}}C{{l}_{4}} \right]\]

    Correct Answer: B

    Solution :

    \[\Delta {{T}_{f}}=im{{k}_{f}}\,\,0.0054\,\,=\,\,i\,\times 1.8\times 0.001\] \[i= 3,\,\,so it is \left[ Pt{{\left( N{{H}_{3}} \right)}_{4}}Cl \right]C{{l}_{2}}\]


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