A) \[\left[ Cr{{\left( N{{H}_{3}} \right)}_{6}} \right]C{{l}_{3}}\]
B) \[\left[ Co{{\left( N{{H}_{3}} \right)}_{5}}Br \right]S{{O}_{4}}\]
C) \[\left[ Cr{{\left( en \right)}_{2}}C{{l}_{2}} \right]\]
D) \[\left[ Cr\left( e{{n}_{3}} \right)C{{l}_{3}} \right]\]
Correct Answer: B
Solution :
The compound which has the same composition but give different ions in solution show ionization. So \[Co{{\left( N{{H}_{3}} \right)}_{5}}Br]S{{O}_{4}}\] is ionization isomer. \[[Co{{(N{{H}_{3}})}_{5}}BrS{{O}_{4}}]\rightleftharpoons {{[Co{{(N{{H}_{3}})}_{5}}Br]}^{2+}}\,+SO_{4}^{2-}\] \[[Co{{(N{{H}_{3}})}_{5}}S{{O}_{4}}]Br\rightleftharpoons {{[Co(N{{H}_{3}})S{{O}_{4}}]}^{+}}\,+Br_{{}}^{-}\]
You need to login to perform this action.
You will be redirected in
3 sec
