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NEET Sample Paper NEET Sample Test Paper-69

  • question_answer
    The uncertainty in the position of an electron (\[\operatorname{mass}\,\,=\,\,9.1\,\,\times \,\,1{{0}^{-}}^{28}\]) moving with a velocity of \[3.0\, \times \, 1{{0}^{4}}cm {{s}^{-}}^{1}\] accurate up to \[0.001\,%\] will be (Use \[\frac{h}{4\pi }\] in the uncertainty expression, where \[h=6.626\times \,\,{{10}^{-}}^{27}\])

    A) 1.92 cm                        

    B) 7.68 cm

    C) 5.76 cm                        

    D) 3.84 cm

    Correct Answer: A

    Solution :

    \[\Delta p = m \times  \Delta v\] \[\Delta p = 9.1 \times  {{10}^{-28}}\times 3.0\times {{10}^{4}}\times \frac{0.001}{100}\] \[\Delta p = .73 \times  {{10}^{-24}}\] \[\Delta x\,\,=\,\,\frac{h}{\Delta p\times 4\pi }=\frac{6.626\times {{10}^{-27}}}{2.73\times {{10}^{-28}}\times 4\times 3.14}\] \[\Delta x\,\,=\,\,1.92\,\,cm\]


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