A) \[34\,\,\mu T\]
B) 74 mT
C) 34 mT
D) \[74\,\,\mu T\]
Correct Answer: D
Solution :
\[{{i}_{net}}=\,\,20-6+12-7+18=37\,\,A\,\,so\,\,B=\frac{{{\mu }_{0}}}{4\pi }\cdot \frac{2i}{a}\] \[=\,\,{{10}^{-7}}\times \frac{2\times 37}{10\times {{10}^{-2}}}=74\times {{10}^{-6}}\,T=74\,\mu T\]You need to login to perform this action.
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