A) \[\left[ Co{{\left( N{{H}_{3}} \right)}_{5}}N{{O}_{2}} \right)C{{l}_{2}}\]
B) \[\left[ Co{{\left( N{{H}_{3}} \right)}_{5}}Cl \right]\left[ Cl\left( N{{O}_{2}} \right) \right]\]
C) \[\left[ Co{{\left( N{{H}_{3}} \right)}_{4}}\left( N{{O}_{2}}Cl \right) \right]\left[ \left( N{{H}_{3}} \right)Cl \right]\]
D) \[\left[ Co{{\left( N{{H}_{3}} \right)}_{5}} \right]\left[ {{\left( {{N}_{2}} \right)}_{2}}C{{l}_{2}} \right]\]
Correct Answer: A
Solution :
The most probable complex which gives three moles ions in aqueous solution may be \[\left[ Co{{\left( N{{H}_{3}} \right)}_{5}}N{{O}_{2}} \right]C{{l}_{2}}\,\] because it gives two chlorine atoms on ionisation. \[[Co{{(N{{H}_{3}})}_{5}}N{{O}_{2}}]C{{l}_{2}}\,\to \,\,{{[Co{{(N{{H}_{3}})}_{5}}N{{O}_{2}}]}^{2+}}\,+2C{{l}^{-}}\]You need to login to perform this action.
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