A) Half of the atomic weight
B) 1/5 of the atomic weight
C) The atomic weight
D) Twice the atomic weight
Correct Answer: C
Solution :
The atomic weight \[Equivalent\text{ }weight\,\,=\,\,\frac{Atomic\,\,weight}{No.\,of\,{{e}^{-}}\,lost\,\,or\,\,gained}\] \[F{{e}^{2+}}\to \,\,F{{e}^{3+}}+{{e}^{-}}\]You need to login to perform this action.
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