A) \[{{\left( \frac{dP}{dV} \right)}_{T}}=\frac{K}{V}\]
B) \[{{\left( \frac{dP}{dV} \right)}_{T}}=\frac{K}{{{V}^{2}}}\]
C) \[{{\left( \frac{dP}{dV} \right)}_{T}}=-\frac{K}{V}\]
D) none
Correct Answer: B
Solution :
From Boyle?s law \[\operatorname{PV}=constant\] \[\operatorname{PdV}+VdP=0\] \[{{\left( \frac{dP}{dV} \right)}_{T}}=-\frac{P}{V}=-\frac{K}{{{V}^{2}}}\] \[~\left( PV=K \right)\]
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