question_answer

When \[N{{H}_{3}}\] is treated with HCl, state of hybridization on central nitrogen

A) \[Changes\text{ }from\,\,s{{p}^{3}}to\,\,s{{p}^{2}}\]

B) Remains unchanged

C) \[Changes\text{ }from\,\,s{{p}^{3}}\,to\,\,s{{p}^{3}}d\]

D) \[Changes\text{ }from\,\,s{{p}^{3}}\,to\,\,sp\]

Correct Answer: B

Solution :

On \[NH_{4}^{+}\] state of hybridisation on central nitrogen, atom is \[s{{p}^{3}}\] as in\[N{{H}_{3}}\].