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NEET Sample Paper NEET Sample Test Paper-69

  • question_answer
    2 moles of \[PC{{l}_{5}}\] was heated in a closed vessel of 2 litre capacity. At equilibrium, \[40%\] of \[PC{{l}_{5}}\] is dissociated into\[PC{{l}_{3}}\,\,and\,\,C{{l}_{\text{2}}}\]. The value of equilibrium constant is

    A) 0.266               

    B) 0.53

    C) 2.66                             

    D) 5.3

    Correct Answer: A

    Solution :

    \[PC{{l}_{5}}\,\,\rightleftharpoons \,\,PC{{l}_{3}}+C{{l}_{2}}\] \[\frac{2\times 60}{100}\,\,\frac{2\times 40}{100}\,\,\frac{2\times 40}{100}\] \[\operatorname{Volume} of container = 2 litre.\] \[{{K}_{c}}=\frac{\frac{2\times 40}{100\times 2}\times \frac{2\times 40}{100\times 2}}{\frac{2\times 60}{100\times 2}}\,\,=\,\,0.266\]


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