A) \[\frac{10}{3}\mu F\]
B) \[\frac{15}{4}\mu F\]
C) \[\frac{12}{5}\mu F\]
D) \[\frac{25}{6}\mu F\]
Correct Answer: A
Solution :
Since, \[\frac{3}{2}=\frac{6}{4}\] the circuit is treated as Wheatstone bridgeYou need to login to perform this action.
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