A) \[{{N}_{2}}\]
B) \[{{O}_{2}}\]
C) both [a] and [b]
D) None of these
Correct Answer: C
Solution :
Sodium nitrate on decomposition upto \[{{500}^{o}}C\] to give \[NaN{{O}_{2}}\] and oxygen. \[2NaN{{O}_{3}}\xrightarrow{\Delta }2NaN{{O}_{2}}+{{O}_{2}}\uparrow \] While at higher temperature i.e. above to \[{{800}^{o}}C\] \[NaN{{O}_{2}}\] is decomposed into \[{{N}_{2}}O,{{N}_{2}}\] and \[{{O}_{2}}\] \[2NaN{{O}_{2}}\xrightarrow{{{800}^{o}}C}N{{a}_{2}}O+\frac{3}{2}{{O}_{2}}\uparrow +{{N}_{2}}\uparrow \]
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