A) \[{{C}_{2}}{{H}_{4}}+HCl\]
B) \[{{C}_{3}}{{H}_{6}}+B{{r}_{2}}\]
C) \[{{C}_{3}}{{H}_{6}}+HBr\]
D) \[{{C}_{3}}{{H}_{8}}+C{{l}_{2}}\]
Correct Answer: C
Solution :
According to Markownikoff?s rule, the addition of a unsymmetrical reagent to an unsymmetric alkene takes place in such a way that the negative part of the reagent will be attached to the carbon atom which containing lesser number of H-atom. Hence it is best applicable to the reaction between \[{{C}_{3}}{{H}_{6}}\] and \[HBr\] \[C{{H}_{3}}CH=C{{H}_{2}}+HBr\xrightarrow{{}}C{{H}_{3}}-\underset{Br}{\mathop{\underset{|}{\mathop{C}}\,}}\,H-C{{H}_{3}}\]
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