A) \[2V\,\sin \frac{\theta }{2}\]
B) \[V\,\sin \,\theta \]
C) \[2V\,\cos \,\frac{\theta }{2}\]
D) \[V\,\cos \theta \]
Correct Answer: A
Solution :
As, velocity of P \[{{V}_{P}}=\sqrt{{{V}^{2}}+{{V}^{2}}+2{{V}^{2}}\,\cos ({{180}^{o}}+\theta )}\] (Where, V= Velocity of centre at mass) \[=V\sqrt{2(1-\cos \theta )}\] \[\Rightarrow \] \[{{V}_{p}}=2V\sin \frac{\theta }{2}\]You need to login to perform this action.
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