A) \[1:2\]
B) \[1:4\]
C) \[2:1\]
D) \[4:1\]
Correct Answer: B
Solution :
Applied potential difference is same \[\Rightarrow \] \[{{R}_{series}}=2\,R\] and \[{{R}_{parallel}}=R/2\] As, Power \[=\frac{{{V}^{2}}}{R}\] \[{{P}_{series}}\propto \frac{1}{2R}\] \[{{P}_{parallel}}\propto \frac{1}{(R/2)}\] \[\frac{{{P}_{series}}}{{{P}_{parallel}}}=\frac{1}{2R}\times \frac{R}{2}=\frac{1}{4}\]You need to login to perform this action.
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