A) \[\frac{10}{3}\mu F\]
B) \[\frac{15}{4}\mu F\]
C) \[\frac{12}{5}\mu F\]
D) \[\frac{25}{6}\mu F\]
Correct Answer: A
Solution :
Since, \[\frac{3}{2}=\frac{6}{4}\] the circuit is treated as Wheatstone bridge \[{{C}_{eq}}=\frac{3\times 6}{3+6}+\frac{2\times 4}{2+4}=2+\frac{8}{6}=\frac{20}{6}=\frac{10}{3}\mu F\]You need to login to perform this action.
You will be redirected in
3 sec