A) \[1:33\]
B) \[1:5\]
C) \[2:5\]
D) \[1:478\]
Correct Answer: B
Solution :
As, the shift to mica is \[S=\frac{(\mu -1)tD}{d}\] and width, \[w=\frac{\lambda D}{d}\] Given, \[S=w\] As, \[t=12\times {{10}^{-15}}cm\] and \[\lambda =b\times {{10}^{-5}}cm\] \[\Rightarrow \] \[\mu =\left( \frac{\lambda }{t}+1 \right)=15\]You need to login to perform this action.
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